Recent content by ToastIQ

Hi! First of all, I am REALLY sorry for replying so late, I've had a really bad influenza. I wasn't asking about Latex in general, I just meant those big brackets that look like wings. I really don't know, I've googled but some things that seem to work on other sites don't seem to work on...

Hi! Just started with linear algebra Could someone help me with this problem? $$ 2x_1 + x_2 - x_3 + 3x_4 - 3x_5 = 0\\ 3x_1 + 2x_2 + x_3 + 2x_4 + 2x_5 = 0\\ -4x_1 + 3x_2 + 2x_3 + x_4 - 4x_5 = 0 $$ (Sorry, I don't know how to do these big brackets for equation systems in Latex.) So it's a...

Yeah I've seen an example on this problem with L'Hôpital's Rule. But we haven't learned about L'Hôpital's Rule yet, and even if we had, we're not allowed to use it in this class.

Hello, I'm supposed to calculate the limit of this: $$\lim_{{x}\to{1}}\left(\frac{x}{x-1}-\frac{1}{\ln x}\right)$$ Combining the fractions: $$ \frac{x}{x-1}-\frac{1}{\ln x} = \frac{x\ln x-x+1}{(x-1)\ln x} $$ The substitute $$ u=x-1 \implies x=1+u $$ then gives...

Thanks! What can I say, Google rarely ever disappoints me as a friend :D I totally agree with you. It just seemed so complicated at first, but it's so worth it.

Yeah sorry, you're right, I really need to learn how to use Latex! :D Jesus. I moved on from this problem long ago, always thinking "There have to be initial conditions" but I couldn't see any. Went back to look again for the 3rd time when you asked and THAT'S when I found out I had been...

I don't know if I'm missing out on something here but I think it said yh=(C1x+C2)e-x which after expanding the brackets should become C1xe-x+C2e-x which is basically the same as C1e-x+C2xe-x or am I wrong? Just that the x is with C1 instead of C2. Does it make a difference if the x is with C1 or...

Thanks for your reply. So I believe my homogeneous solution was correct? I know that there can't be any terms in the particular solution that are a solution to the homogeneous equation. I can't fully wrap my head around why though. Can you see right when starting with the particular solution...

Hi! I'm having a hard time with general solutions of a certain type, maybe it has to do with the constant in the particular solution? The equation is y''+2y'+y=xe-x+1 Is it right to assume that yh=(C1x+C2)e-x ? For the particular solution, I've tried all kinds of guesses for the form: yp=...

Thank you for your reply. I actually remember trying this alternative too. This gave me the right coefficient for C1 but I still got it wrong for C2. I tried again and saw I had the wrong derivative for C2xe-3x. That solved the problem. Thanks a lot! :)

Hi! I've been stuck on this problem for 2 days. I'm new here and I've just spent another hour on trying to figure out Latex, but it always ends up in a mess so I'll try without. I hope that's okay. The equation is y''+6y'+9y=4e-x with the value boundaries (I think that's what it's called in...