Sorry to bring up an old thread, but I was under the impression that the energy absorbed by the tree will be equal to 1/2QV, and not QV. I'd be curious to hear what others have to say about this.
Thanks,
Tom
Homework Statement
I’m trying to find the drift speed of electrons in a copper wire. The length of the wire is 10 meters, temp is 60°C, current is 5 A and the total resistance of the wire is 0.05 ohms.
Homework Equations
# of charge carriers (n) = density * 6.02 x 10^23/molar mass...