Recent content by Tomaz Kristan

Do you know, that this is not the case? You and I could be forced to accelerate in the opposite directions, yet the center of the mass of the you&me system, would not move at all. Let alone to be accelerated. Just one example.

First of all, the force to the mass center is NOT the sum of all forces. Not at all. Do you know that?

What is your point? That it is all OK, if all the net forces, to every ball, are finite and left pointing, as long as the force to the mass center is divergent? Is that your point?

> Well I'm settled on the finite force on every individual ball part. Fine. Everybody else also? > Your paradox revolved around the fact that the center of mass of a closed system was supposedly moving. It can also revolves around the strange fact you admit. Only left pointed forces at t=0. A...

I don't care for the mass center. I care only for the mass particles. I am glad that you agree with me about those. > Could you give your proof that this force is also finite. I could, after this is settled with the majority here. That all balls are forced to the left hand side.

Good! What was the answer? Was it ... that a finite force is affecting every ball? All pointed to the left? At least at t=0? :smile:

Even (G*m*m/2)/(d*d)+(G*m*m/4)/(d*d*1.1*1.1)+(G*m*m/8)/(d*d*1.11*1.11)+...+... < G*m*m/(d*d) would be quite enough. The left side force is finite. Also always exceeds the right side force. No more is needed, no fancy math can change this strange fact. :cool:

I repeat myself: >> (G*m*m/2)/(d*d)+(G*m*m/4)/(d*d*1.1*1.1)+(G*m*m/8)/(d*d*1.11*1.11)+...+... = (0.992*G*m*m)/(d*d) It's trivial to see that.

The left side is quite weak, but I don't care. At least not more than for the OMF's calculation somewhere above. But the right side is correct and that's enough.

Looks quite good to me.

Calculation The right side force to mass point m is: (G*m*m/2)/(d*d)+(G*m*m/4)/(d*d*1.1*1.1)+...+... = (0.992*G*m*m)/(d*d) What else do you need?

> And the sum of all the forces on all the balls is infinite. The sum of all forces on all balls doesn't count. You can tile a cube to have the same "effect" of the "infinite sum of all forces". It is not I who trolls here, OMF. What only matters is: The sum of all the forces, to...

The sum of all the forces, to every ball is finite, yes. Negative, but finite.

This is one reason, why your calculation is wrong. Means nothing. The sum of all forces between various parts of a rigid body can easily be divergent. So what?

Luke, I don't give any guaranties to my example changed in any way. A modification still may be no good (what's the whole intent), but I stand only behind my construction. Here, it's not the infinite amount of energy, what is the problem. It's the rebellion against the Third Law of Newton...