Recent content by tornado681

Defennder, How do you rewrite u in terms of y only? Can it be done?

anyone?

anyone care to comment on the solution?

When I solve u' = -ayu - by I get: \frac{u}{a}-\frac{b}{a^2}ln[|{au+b}|]+C_1 =-\frac{1}{2}y^2 + C_2 So then we need to make the above equation u=u(y) correct? Since we have a ln (natural log), is this possible? Any more help is most appreciated. Thanks, --tornado

defennder, I understand how you get: u' = -ayu - by when you set y'=u I don't understand how u'=u du/dy . I appreciate you trying to work me through this. Any additional explanation would be appreciated. Specifcally, how is this so: --tornado

slider, Im not following you. Could you go into a let more detail if possible. Thanks, --tornado

Hello all, This is the first time I've stumbled across this site, but it appears to be extremely helpful. I am a meteorology grad student, and in my research, I have run across the following 2nd order non linear differential equation. It is of the form: y'' + a*y*y' + b*y=0 where a...