Recent content by Travis McWilliams

So, I have a hydraulic cylinder in which the base is an ellipse. It measures 1.4375 by 2.0625. I find the area with (a x b x pi) which = 2.33. Then I find the output force with ( PSI x Area ) which = 23,300. Then I would multiply 23,300 by the radius (1.5) of second gear, which I'm getting...

I get it, ahh that was my first thought and then I started overthinking again. The force applied on the second gear would have a constant mechanical advantage... spoke too soon

Ok wow, that is way more simple than I thought. So, it should be: Force from cylinder x the diameter of first gear = first gear output and then First gear output x radius of second gear = final output torque f x d = op op x r = t Is that right? Thank you very much for...

Also, I believe I know which sub sea torque tool you're refferring to. Did It have a "rooster tail" extruding from the hex and a cylinder attached to an arm which went around another bolt a couple of bolts from the bolt being torqued? If so, those are old school wrenches, quite dangerous...

JBA, correct on the confined space issue. But, no ratcheting. I have left out other major details which would clearly explain my design. I'm just nervous about sharing those details, if you know what I mean... On just about every low clearance hydraulic torque wrench, double acting cylinders...

yes, there are plenty of hydraulic torque wrenches on the market which are much simpler than what I'm doing here. however, I just really would like to figure out how to solve this, it's nagging at me!

It will be used to torque a bolt. 1 7/8" stud - 2 15/16" nut.

Anyone?

Everything will be all buttoned down. "final" will not move on its own.

Also, everything is a variable except, "final gear" It must be 3" And the cylinder can push at any angle. I was thinking at a 90 degree angle would be the most efficient and allow the most mechanical advantage...

Ok, so the CAD program I use is still under development and is very buggy. I did a quick model, The cylinder is not to proportion. The cad program crashed before I could save any of my individual models, so this is the best I can do at the moment. However, the cylinder will push the two bars...

Let me get a sketch together, with dimensions.

Guys, I'm trying to figure some stuff out, but I'm stumped. I need to figure the what my output would be. I'm applying linear force via hydraulic cylinder. The cylinder will turn a "gear" and in turn turn another. The "gear" is not necessarily a gear, it and the hydraulic cylinder will mate...