Recent content by tristan401
-
T
Distance traveled by projectile
Velocity - m/s Acceleration - m/s^2 Time - s distance - ?- tristan401
- Post #9
- Forum: Introductory Physics Homework Help
-
T
Distance traveled by projectile
I don't think I do :(- tristan401
- Post #7
- Forum: Introductory Physics Homework Help
-
T
Distance traveled by projectile
d = (12150 m/s) (0.129 s) + 1/2 (94186 m/s/s) (0.129 s)^2- tristan401
- Post #5
- Forum: Introductory Physics Homework Help
-
T
Distance traveled by projectile
When I plugged everything into the equation, it looked like: d = (12150)(0.129) + 1/2(94186.05)(0.129)^2 which resulted in 2351.025 I don't know if that's cm or m or km, but that's the number that came out out of the equation- tristan401
- Post #3
- Forum: Introductory Physics Homework Help
-
T
Distance traveled by projectile
Homework Statement Suppose you have a projectile of 120g. Suppose that projectile is accelerating at 9186.05 m/s/s for 0.129 seconds, to a velocity of 12150 m/s. Factoring in a 20% drop in Velocity from aerodynamics and friction, it accelerates to roughly 9750 m/s. What distance did the...- tristan401
- Thread
- Distance traveled Projectile
- Replies: 9
- Forum: Introductory Physics Homework Help