Recent content by TristanJones

welp, cheers!

there are no massless particles in this equation though ... sorry, I'm just not entirely sure if you're agreeing with my end result, or implying I should make changes

unless you got something entirely different and I am to to lunch, hehe

ok, then I used that, calculated gamma, and inserted back into the momentum equation to solve for m3 and got 3.873 u. should be good to go. thanks!

@Ray Vickson - ok, so for the momentum I got γ3m3v3= 1uC for energy I got: γ3m3= 4u so I divide the first one by the second to get v3= 0.25c (?)

gahhh, you're right. i think my issue was dealing with the one particle which was at rest (and has no momentum). i'll play around with it a bit

and whatever V3 would be in the momentum equation (unless I'm not supposed to use the momentum equation)

do you mean eliminating the v as a variable? i used the conservation of energy and momentum formulas, but there's just something not quite working. i end up with more unknowns than i know what to do with

Homework Statement [SIZE=13px][FONT=Helvetica]Q: A 3.000u object moving to the right through a laboratory at 0.8c collides with a 4.000u object to the left of the laboratory at 0.6c. Afterward, there are two objects, one of which is a 6.000u mass at rest. A) what are the mass and speed of the...