Recent content by TROGLIO

what is hadamard theorem? enlighten me thanks

this is an old sum of IIT JEE try and see the solution the same sum is also there in H C VERMA the solution of that book is available you start by cutting tha capacitor into smaller capacitors so thickness dx parallel to the plates of the capacitor than take the slope of the dilectric...

jonny you haven't taken into account that fact that the bullet will get deformed so energy will be used to do that hence the energy conservation idea is tough as v do not know how much energy is used in deforming the bullet tried balancing torque? the bullet wil produce a torque...

press is proportional to volume so let's ay press = k x vol now work done is dw = (integral) p x dv pure math actually not much physics

i can't reply in tech terms bcoz i dnt know much f them so excuse m for that i meant superposition fill the hole with + and - anperes law wouldn't work bcoz of lack of symetery amperes law works some wat like gauss law in electro

amperes law will not be valid in this case revise your notes and you will see why "fill" the hole with +current and equal -current so the net current remains 0 now club the +current of as 1 single wire and calculate its magnetic field at the desired point and similarly for the -current then...

how can u solve it wothout knowing d charge of d 3rd sphere??

1/t - 1/t^2+t add and substract t in d numerator of -1/t^2+t

nice 1 pure genius i need some help with modulo theory i dnt know a thing about it any free e books or any material would do

n^3 - n nx(n^2 -1) n x (n-1) x (n +1) let's say this = A now consider (n+1)C3 ie the number of ways of choosing 3 objects from n+1 it wil always b an integer (n+1)C3 = integer i can't chose half an object (n+1)C3 = (n+1)x(n)x(n-1)/3 integer = A/3 hence A is divisible by 3

done by binomial theorem don't know mod theorem 3^56 (3^4)x(3^52) 81x(9^50) 81x[(10-1)]^50 or 81x[(1-10)]^50 81x[1+50x10+(50x49x100)/2 +(50x49x48x1000)/6 . . . . . 10^50] from the 3rd term onwards al the trems are divisible by 1000 hence by dividing the first 2 terms by 1000 i wil get...