Recent content by Tsss
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Undergrad What Are the Legal Steps in Calculating i^i?
The fact that (a^b)^c=a^{bc} is not right with complex numbers. As a matter of fact, let z a complex number, e^z=e^{\frac{2i\pi z}{2i\pi}}=(e^{2i\pi})^{\frac{z}{2i\pi}}=1^{\frac{z}{2i\pi}}=1 there is a problem.- Tsss
- Post #9
- Forum: General Math
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Example of Xn + Yn Limit | Help with Problem
X_n=\sum_{k=1}^n 1 Y_n=\sum_{k=1}^n -1- Tsss
- Post #5
- Forum: Introductory Physics Homework Help
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Solving a Tricky Sum: Convergence of \sum_{n=1}^{\infty} a_{n}
n\ln(1 - \frac{1}{n^2})\sim-\frac{n}{n^2}=-\frac{1}{n}\rightarrow 0 So, (1 - \frac{1}{n^2})^{n}-1=e^{n\ln(1 - \frac{1}{n^2} )}-1\sim-\frac{1}{n} Now, you can conclude ;).- Tsss
- Post #12
- Forum: Introductory Physics Homework Help
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Graduate Proving the Sum of Complex Numbers on the Unit Circle
What does w<=2 mean for a complex number ? -
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Graduate Infinite Product of (1+a2n-1)(1+a2n) - Math Help
I would like to add something about sequences and subsequences. That's right that you can't conclude about the convergence of a sequence only working on his subsequences...in the most cases. Indeed, if two subsequences has two different limits, then the sequence has no limit (because if a...