Ah! Great! The substitution explained for me! Thanks!
Right now I'm struggling with:
\int^{\pi}_{-\pi}\frac{1}{1+sin^{2}{\theta}}d\theta
when rewritten:
\int_{C}\frac{1}{1+(\frac{z-z^{-1}}{2i})^2}\frac{dz}{iz}
\int_{C}\frac{4}{4-(z^2-2+\frac{1}{z^2})}\frac{dz}{iz}
which I get to...
Hi!
I have learned how to solve equations like:
\int^{2\pi}_{0}\frac{1}{1+sin\theta}d\theta
using
\int^{2\pi}_{0}F(sin\theta,cos\theta) d\theta
\int_{C}F(\frac{z-z^{-1}}{2i},\frac{z+z^{-1}}{2}) \frac{dz}{iz}
How do I solve equations of the type...