Recent content by tuite

Ah! Great! The substitution explained for me! Thanks! Right now I'm struggling with: \int^{\pi}_{-\pi}\frac{1}{1+sin^{2}{\theta}}d\theta when rewritten: \int_{C}\frac{1}{1+(\frac{z-z^{-1}}{2i})^2}\frac{dz}{iz} \int_{C}\frac{4}{4-(z^2-2+\frac{1}{z^2})}\frac{dz}{iz} which I get to...

Hi! I have learned how to solve equations like: \int^{2\pi}_{0}\frac{1}{1+sin\theta}d\theta using \int^{2\pi}_{0}F(sin\theta,cos\theta) d\theta \int_{C}F(\frac{z-z^{-1}}{2i},\frac{z+z^{-1}}{2}) \frac{dz}{iz} How do I solve equations of the type...