Recent content by Tuomo

Thanks fluidistics. Ok, so, what I get is: \frac{dx}{du}=\frac{dx}{dt} \cdot \frac{dt}{du}=\left[y(u(t)) \cdot z(u(t)) + u(t)\right] \cdot \frac{dt}{du(t)} Now, what the heck is this \frac{dt}{du(t)} ? Any idea how should I treat it? Is it just a reciprocal of \frac{du(t)}{dt}? In...

I have derivative dx/dt = y(u(t)) * z(u(t)) + u(t) Now, what is dx/du ? I know the chain rule should help, but I am stuck :-(