Recent content by Tyrone123

I don't mean anything in particular, just me trying to isolate x in the equation

Hmm.. so far I have at least gotten rid of the log part, and I now have: \frac{\sqrt{x^2 +1}}{cos(x)} = 10\frac{3}{20} Which I can rearrange a bit.. but that cos(x) is causing me troubles!

Not really.. I end up with a slightly prettier equation, but I am not sure how to isolate x from log(cos(x)

Possibly, ill try

woops, I edited log to log10.. and suddenly the equation was gone :b

Homework Statement Im supposed to calculate the value of x for 20*log10(\frac{\sqrt{x^2 +1}}{cos(x)}) = 3 The Attempt at a Solution I start off by dividing by 20 on both sides so I just have the expression with log.. and my idea henceforth is to take the inverse of cosine to...

"just" :3 Expanding the desired expression with the trig identity I mentioned equals V0(t) = A * (cos(w*t) * cos(θ) - sin(w*t) * sin(θ)) and equating it to http://puu.sh/19J7t where the coefficient of cos(t*w) is \frac{k}{(W^2 *R^2 *C^2) } and the coefficient of sin(t*w) is...

If we can agree that http://puu.sh/19J7t is the result to the first part, namely finding an expression for the real part of the equation v_p * ei*w*t.. then so far so good. The next part, which is to rewrite that expression to the form V0(t) to the form V0(t) = A * cos(ωω*t + θω) I...

I realize my mistake and I have now ended up with the following equation for vp by multiplying both the denominator and numerator by the conjugate of the denominator http://puu.sh/19J1F (having issues with the fraction feature, so excuse me pasting an image instead) the above expression for...

Homework Statement The mill (single phased) is now affected by a load from a resistor. We assume that the turbine can deliver an infinitely large current without affecting the frequency. figure 1 illustrates the load: http://puu.sh/19GGR The voltage over the capacitor can can be...