Recent content by Ultimsolution

I am not discussing here the limit when x approaches -3...it's been estblished many posts ago that it is -1... When HalsoIvy said that it would be a lot more interesting to evaluate that limit when x---> 0, he/she awakened my curiosity and I evaluated it and found thatit doesn't exist...It...

Of course that limit would not exist ...right?

Hey, here is how i would approach the problem : Lets start the the square root part , squareroot of (X^2) = absolute value of x , now as x approaches -3 , x is negative which means that absolute value of x = -x ( hopefully you see where I'm going with this. Now what you've got here...