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Pre calc word problem Parabolic archway
hey thank rl.bhat for the welcome. so i think i got it... first 16=4*P(x) where x=2 therefor P = 2 2nd y^2=4(2)(12) Y^2 = 96 y=4 \sqrt{6} then 2y = 19.6 meters- unrealmatt3
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- Forum: Precalculus Mathematics Homework Help
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Pre calc word problem Parabolic archway
Homework Statement A Parabolic archway is 12 meters high at the vertex, at a height of 10 meters, the width of the archway is 8 meters. How wide is the archway at ground level? Homework Equations given in the picture it has (-4,10) and (4,10) along with vertex (0 ,12) The Attempt at...- unrealmatt3
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- Forum: Precalculus Mathematics Homework Help