Well I have an equation for the Kinetic energy now, I've taken the kinetic energy in relation to the centre of mass and then added the kinetic energy from the rotation with the moment of inertia.
I have (x. means x differentiated wrt t, I wasn't sure how to show it on here)
KE = 1/2[Mx.^2...
Homework Statement
A uniform rod AB of mass M and length 2l attatched to a slider at A which is constrained to move along a smooth horizontal wire. The rod, which is subject to gravity, is free to swing in the vertical plane containing the wire. Using Ω (the angle between rod and vertical)...