Recent content by user100

Thanks for the reply. But can u explain further regarding "If the sides were sloping either way than the contributions of pressure on the sides would need to be added in (or subtracted)." i.e the instances where weight would be higher than pressure or vice versa, when sopes are slanting...

ok. But assume i have the base made of glass which can withstand only 395 kg of weight So if i fill the tube (with base of 200cm2) to a height of 10 metres. As u had explained the capacity will be 200 litres fresh water, if it's a vertical tube. Then, when the water reaches 10 metres height...

It is a established fact that pressure i.e ρgh will be same at a given depth. Suppose in a tank filled with water the gauge pressure works out to 1 bar, then the total pressure at the depth of tank would be 1 bar + 1 bar atmospheric pressure = 2 bar pressure. 2 bar pressure equals 2 kgf/ cm2...

Ok sir, understood. If i want area of circle as 2000 sq.cm, using formula ∏r2, we can get radius as .2524 m Then the volume for 15 m height will be ∏r2h, so volume is 3000 litres. Since density of 1 litre water is almost equal to 1 kilogram Weight(mg) will be 3000 * 9.8 = 29400 / 2000...

Yes. Sorry if i wasn't clear. it's my first post. 1. Yes, the base is circle. 2. Let me explain how i arrived at the working. From wiki and other sites, i learned that Pressure increases 1 bar or 100 kpa for every 10 metres depth. So the depth is 15 m, so 1.5 bar. I also understood that...

Hi all, Can someone clarify whether the following is right? Assume a Cylindrical tank with a base area of 2000 sq.cm, is filled with water upto 15 metres ( tank starts from ground level) 1) The pressure at the bottom of tank will be 2.5 bar ( approx) i.e 1 bar pressure for every 10...