Recent content by v3r
-
V
Total Angular Momentum of the Earth
r in I would be the perpendicular distance which would be the radius of the earth. r in Ltrans would be the distance to the center of mass which would be the distance of Earth from sun? I want to solve for v in order to get the time by dividing it by the radius?- v3r
- Post #5
- Forum: Introductory Physics Homework Help
-
V
Elastic Collision of Two Particles: Solving for Final Velocity
Elastic means no change in internal energy DeltaE = 0 DeltaK + DeltaEint = 0 DeltaK = 0 Kf1 - Ki1 + Kf2 = 0 0.5mvf1^2 - 0.5mvi1^2 + 0.5(3m)vf2^2 = 0 0.5(3m)vf2^2 = 0.5mvi1^2 - 0.5mvf1^2 There's two unknowns, vf2 and vf1 Is this setup wrong?- v3r
- Post #3
- Forum: Introductory Physics Homework Help
-
V
Total Angular Momentum of the Earth
So it should be Ltot = Ltrans + Lrot Ltot = 0 Ltrans = Lrot mvr = Iw mvr = 2pi/T * I mvr = 2pi/T * mr^2 v/r = 2pi/T I'm still confused.- v3r
- Post #3
- Forum: Introductory Physics Homework Help
-
V
Elastic Collision of Two Particles: Solving for Final Velocity
Homework Statement Particle 1 of mass m moving with speed v in the +x direction has an elastic collision with particle 2 of mass 3m which was originally at rest. After the collision, particle 2 is moving in the +x direction. What is its speed? Homework Equations deltap = 0 pf1 + pf2 =...- v3r
- Thread
- Collision Elastic Elastic collision
- Replies: 3
- Forum: Introductory Physics Homework Help
-
V
Total Angular Momentum of the Earth
Homework Statement How long should the day be so that the total angular momentum of the Earth (including its rotation about its own axis and its (approximately) circular orbit around the sun) is zero (Note: the magnitude of the angular velocity is 2pi/T where T is the period of rotation?)...- v3r
- Thread
- Angular Angular momentum Earth Momentum total angular momentum
- Replies: 5
- Forum: Introductory Physics Homework Help