Recent content by v4valour

The polar form results in : (reitheta)6=re-itheta e6itheta=e-i theta e7itheta=0 cos(7theta) + isin(7theta)=0

Hi I have tried r5( cos(5 theta) + i sin(5 theta) ) = r( cos(theta) +i sin(theta) ) but this lead to: cos(5 theta) = cos (- theta) and i sin(5 theta) = i sin(-theta) which is very difficult to solve without a calculator. Using the polar form results in similarly difficult equations. Thanks

Homework Statement The problem states that you need to solve the following equation (without a calculator) : z^5 = z̅ Homework Equations z=a+bi and z̅=a-bi The Attempt at a Solution So far I've tried multiplying both sides by z̅: z̅ * z^5 = |z̅|^2...