Recent content by Vantom

inverse 1/2 + 1/2 + 1/4 = 0.8 then i add 0.8 to the single 4 Ω and the sum = 4.8 i was only confused by the parallel and series situation as the circuit is rotated thank you

so 2 Ω and 2 Ω and 4 Ω are in parallel and the 4 Ω alone is in series i have to sum the parallel ohms to replace them with a single resistor of 8 right ?

4 Ω and the other 4 Ω are in parallel while 2 Ω and 2 Ω are in series

its the same answer (2) as mine but the problem is i don't know how to add it to the other ohms in series so i can get the total resistance

1/4 + 1/4 = 2 that's the total of the parallel resistors but from there i don't know how to add it to the sum of the series resistors to get the total answer

for parallel i use the formula 1/r1+1/r2+1/r3 but this one is a complex of both parallel and a series

here is the question below with all the possible answers, if anyone can help it would be appreciated