Well...i just like solving problems i come up with...
So suppose you have a rotating inclined plane and the angle of inclination is a function of time such that...angle 'x'=angular velocity(w)*time(t)
now mgsin(x) is the horizotal component of g so the body on the frictionless inclined...
I Think this is the solution...
for the body to accelerate horizontally then the forces on m are
External Force F
Frictional force -mgf
Force due to the spring -kx
Force Due Friction on M MgfMgf=2mgf
F-(mgf+kx)>2mgf
F>3mgf+kx
F>12+kx If k is negligible then
F>12 Newtons
If the angle of a frictionless inclined plane 'a' is such that a=wt
where w is angular velocity and a is a function of t
and an object is sliding down that plane then...
if m is the mass of the object
m(dv/dt)=mgsin(wt)
solving for v i got
v=(-gcos(wt)/w)
Why is the velocity...