Recent content by Vatsa

Well...i just like solving problems i come up with... So suppose you have a rotating inclined plane and the angle of inclination is a function of time such that...angle 'x'=angular velocity(w)*time(t) now mgsin(x) is the horizotal component of g so the body on the frictionless inclined...

I Think this is the solution... for the body to accelerate horizontally then the forces on m are External Force F Frictional force -mgf Force due to the spring -kx Force Due Friction on M MgfMgf=2mgf F-(mgf+kx)>2mgf F>3mgf+kx F>12+kx If k is negligible then F>12 Newtons

If the angle of a frictionless inclined plane 'a' is such that a=wt where w is angular velocity and a is a function of t and an object is sliding down that plane then... if m is the mass of the object m(dv/dt)=mgsin(wt) solving for v i got v=(-gcos(wt)/w) Why is the velocity...