Recent content by vboyn12

Oh, I see :D. Thank you a lot

can you give me your solution corresponding to your assumption, please?

It is not conducting

Do you get the same result as mine for part (c)?

Sorry about the unit :D. For part (c), is that the value of charge Q found in part (a) equal to the surface charge density multiply by the surface area which is 4pi*r^2? If that is right I get rho(s)=11,789 nC/m^2

Hi, I try to solve part a and b and i posted below, can you have a look at it?

Can you take some time to have a look at another topic of mine?

thank you a lot.

So we have to take a double integral of the flat base with limits r from 0 to 1 and phi from 0 to 2pi, i guest

theta from 0 to pi/2, is it correct?

thank you. Can you give me some hints to do part (b), please?

I think it must be 20 because when taking partial derivative of D(theta component)*sin(theta) respect to theta we can obtain derivative of sin(theta)^2=2sin(theta)cos(theta). This is the first time I post thread so excuse me about the math formulas