Homework Statement
For a 98 kg person standing at the equator, what is the magnitude of the angular momentum about Earth's center due to Earth's rotation? Assume the Earth has a radius of 6.4 x 106 m.
Homework Equations
Angular Momentum = rmv * sin(theta)
The Attempt at a...
I understand that KE = 1/2mv^2, so when I tinker around with that I get
V = sqrt (2KE/m)
But that equation gives me a problem cause I can't just make KE a variable like that. I do know that all of the energy at the bottom is KE though. So:
1/2mvi^2 + sqrt(2gh) = 1/2mvf^2
When I take...
I know if there was no initial velocity, the velocity at the bottom would just be sqrt(2gh), but I'm not sure how the initial velocity impacts the velocity at the bottom. I thought just adding the x-component of the velocity would be enough but apparently it's not :\