Recent content by Vick007

Homework Statement Two train cars are on a straight, horizontal track. One car starts at rest and is put in motion with a constant acceleration of 2.1 m/s2. This car moves toward a second car that is 25 m away and moving at a constant speed of 3.6 m/s. (a) Where will the cars collide...

ok so I got like X = 31.86 meters? is that correct?

would it be one like this? X - Xo = .5(Vo + V)t which could be simplified to X = .5(5+V)(12.74) how do I find the velocity though?

so V2 = 0 and now I just have to find T so according to your equation it would look like this: v2 = v1 + a*t and if I fill it in I get 0 = 5.00 + (-.3924) * t -5 = -.3924 * t (-5/-.3924) = t t = 12.42 sec (is that correct?) thanks a lot for helping, but there's a second part to the...

the initial velocity is 5.00 m/s and since the acceleration is (I think) -.3924 and I'm looking for the time would this equation work? a = (V2 - V1)/T where (V2 - V1) = change in velocity so it would say -.3924 = (V2 - 5.00)/T but what is V2? or how do I find it?

Ff= force of friction U= coefficient of friction Fn= force normal m=mass g=acceleration due to gravity =9.81 a= acceleration d=distance Ff=UxFn which is the same as m x a= U x m x -g divide out the m and you get a=U x -g and so a=.04 x -9.81 a= -.3924 so is it slowing down by...

weight X coefficient of friction = friction force? how does that tie in with the velocity given?

ok so I checked and yeah the coefficient is given as 0.04 what do I do now? thanks

Homework Statement With an initial speed of 5.00 m/s a 1.00 kg disk is slid on a horizontal steel plate. How long will it take for the disk to stop, and how far does it travel? ( do not neglect friction ) Homework Equations I don't know how to use the mass in any equations. help...