Recent content by victorbomba

Sorry, I wasn't paying attention. That was a suggestion for a substitution to solve the integral which you had already correctly solved, but I think it was the wrong integral as the answer certainly diverges as z goes to infinity. Isn't the numerator in the expression...

Might try \tan{\theta} = \frac{r}{z}

(\nabla \times v)^i = \frac{1}{\sqrt{g}} \epsilon^{ijk} (dv)_{jk} - in a coordinate basis.