To find the Thevenin impedance you have to short circuit the voltage source. It seems the load resistor RL is obstructing your imagination. Forget about RL. The short circuit across the voltage source connects the junction of the 30 Ω and 20 Ω resistors to the junction of the 60 Ω and 20 Ω...
Your equations are correct. But the calculation appears to be incorrect. Probably you have not converted km/h into m/s. Try once again and finish both calculations.
You have already found the horizontal component. The final vertical component of velocity just before hitting the ground can be found as usual since you know the initial vertical component (let us say, ‘u’, which is 39.1 m/s), the acceleration ‘g’ (which is 9.8 m/s^2) and the displacement (let...
Write the X-component of velocity as Vcosθ and not as Vx cosθ. Similarly, write the Y-component as Vsinθ and not as Vysinθ.
Since you are asked to find the components of velocity, the question is simple. Gravity cannot change the horizontal component (X-component, as you have imagined). So, its...
The total energy is negative (-GMm/2r)as you have written. The potential energy also is negative (-GMm/r). The kinetic energy is positive and is equal to +GMm/2r. Therefore, the kinetic energy is greater in an orbit of smaller radius.
Once you note the significance of the negativeness of the...
I think the question of using the term ‘impulse’ comes into picture when a force comes into play. Otherwise you will have to say that all moving bodies have impulse and the terms ‘impulse’ and ‘momentum’ will have to be used without any distinction. [You never think of the term ‘impulse’ in the...
Impulse.?
A moving object has momentum. It can give an impulse to another object and in the process receive an impulse. Both will have their momenta changed, but the law of conservation of momentum holds good.
It won’t be proper to say that an object has impulse. You can say that an object...
Since you want to calculate the thickness ‘t’ of the film using the transmitted system, use the equation, 2 n t cosr = mλ where ‘n’ is the refractive index ‘m’ is the order of the interference band and ‘λ’ is the wave length.
The lower order (m) will be for the longer wave length (λ1 =...
You are considering the transmitted system (and not the reflected system), I presume. The condition for brightness in the transmitted system is the one you have written. You will get two values for ‘n’ on substituting the two given values of the wave length. What are you going to calculate?
If...
I was referring to the special case of finding the force F which will keep the blocks stationary relative to the cart. In the general case, the situation is entirely different as you pointed out.
The correct answer indeed is F = m2g(m1+m2+M)/m1.
The answer I gave in a quick (in fact, too quick!) response was incorrect with m1+m2 in the denominator, in place of m1.
The masses m1 and m2 are at rest relative to the cart and hence their acceleration is zero. So we have the following two...
Your answer is correct. The acceleration produced in m1 and m2 by the driving force m2*g should be equal to the acceleration produced in the entire system by the driving force F. Therefore, you have, m2*g/(m1+m2) = F/(m1+m2+M) from which F = m2*g(m1+m2+M)/(m1+m2)
Wind is basically moving air. So, the medium through which the sound is propagated is moving and the velocity of wind is added vectorially to the velocity of sound. That's why the frquency of the sound heard by a listener depends on the wind velocity. How far the sound will reach certainly...