Recent content by villsen

Nevermind i figured it out myself. Just forgot the sine in the differential angle: dΩ=sin(θ)dθdϕ

I have a question regarding the calculation of the cross section in muon pair production from electron positron annihilation. After some calculations the textbook comes to the conclusion that the differential cross section is approximately equal to: (1+cos(theta)^2)alpha^2/(4*s) where alpha...