Recent content by vip89

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    Solve a Challenging Ellipsoid Problem Today!

    ya I am from UoS Why?? whze this??
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    Graduate Can you help me in this problem?

    I did it by school method but doctor said that he want a calculus?? I didnt know how to solve by calculus?
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    Challanging Problem It is nessecary to solve quicly

    How I can complete the question?? I know that L>1 I think I must verify that the opposite of l v’ l > L^2/(L-1) is wrong pls help me today?
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    Graduate Challanging Problem It is nessecary to solve quicly

    That is my solution How I can compleat it??
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    Graduate Can you help me in this problem?

    That is my try
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    Graduate Solving a Serious Math Problem

    that is wt I did,pls send me ur help
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    Solving for Nondecreasing Continuous Functions: g(x+g(y))=g(g(x))+g(y)

    That is wt I did:
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    Challanging Problem It is nessecary to solve quicly

    tHESE R my trials pls tell me wt I must do??
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    Volume Formula for Ellipsoid (a,b,c > 0) using Calculus: Slicing and Rotation

    Continue:
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    Volume Formula for Ellipsoid (a,b,c > 0) using Calculus: Slicing and Rotation

    These are my trials I have the idea but can't get the right answer pls reply THNKX
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    Volume Formula for Ellipsoid (a,b,c > 0) using Calculus: Slicing and Rotation

    I trid to solve it by this way,but strang things will appear,the equation be more complicated!
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    Challanging Problem It is nessecary to solve quicly

    How u jumped from "The average velocity is 1 and since the position function is continuous (since its differentiable) and v(0) = 0 = v(1)" To "L > 1." Is it a rule ?Give me the sorce u got that from If not ,how u profed it??
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    Solving for Nondecreasing Continuous Functions: g(x+g(y))=g(g(x))+g(y)

    ok I will try and I want to say that is not cheating because It is not homework
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    Solving for Nondecreasing Continuous Functions: g(x+g(y))=g(g(x))+g(y)

    ok , it is not important can u solve it ,pls??
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    Solving for Nondecreasing Continuous Functions: g(x+g(y))=g(g(x))+g(y)

    I have acomption with my friend ,who find the answer first