Recent content by Wadah

  1. W

    Fields in a capacitor before and after adding a dielectric layer

    please can you explain to me how this is possible with E (medium) -E (vacuum) = Q_bound / epsilon_0A
  2. W

    Fields in a capacitor before and after adding a dielectric layer

    In this case, it is in a vacuum D = sigma Because we have no free charges in vacuum E = Q_tot / Aepsilon_0 In medium is D = sigma E = Q_tot / Aepsilon and the E-field for the bound charge becomes E_mediumA-E_vakuumA = Q_b / A epsilon?
  3. W

    Fields in a capacitor before and after adding a dielectric layer

    we have a constant charge in capacitor. If the D-field in vacuum is equal to sigma and in medium it becomes equal to sigma free (for free charge). since I know that the D-field should be constant so sigma = sigma free. am I right? I have calculated the E-field in vacuum and got that E = Q /...
  4. W

    Fields in a capacitor before and after adding a dielectric layer

    relevant eduation