ok so I've spent all day on it and I think I've finally got it.
1/10 +1/10 + 1/10 = 0.3
1/0.3 = 3.3 recurring
Qt = 3.3 recurring * 12 = 40
40/10 = 4 (4V drop across each capacitor)
40/10 + 40/10 +40/10 = 12V (Applying Kirchoff's law to check)
can you confirm that this is the way you...
so I can work out the charge for C1 by 10x10-6 x 12 = 120uC however I don't know how to apply that in a way to find the potential difference.
I understand that between each capacitor on this circuit it will drop 4V and 40 micro coulombs
However I don't understand how to use this information...
VT/CT =3.6uF VT being voltage total of 12V, CT being Capacitance total of 3.3uF recurring
from the formula provided it states that I now times that answer by C (i'm guessing means capacitance) this does not give me the expected figures.
I'm thinking that the formula provided is incorrect...
Hi,
I'm having a problem with this circuit finding potential difference between capacitors. I know the answers by playing around on simulation software A=12v B=8v and C=4v however, I am struggling to use the formula provided Vc= (Vt/Ct)*C to find the answers. It works fine in a parallel circuit...