Recent content by watabi

Wait so solve sin^3(9x)? Not sure how that would help but maybe it would go something like: integral sin3(9x)dx integral sin2(9x)sin(9x) we know that sin^2(9x)= 1-cos^2(9x) so change it up and distribute giving integral sin(9x)-integral sin(9x)cos2(9x) which gives me (-1/9)cos(9x)-integral...

Homework Statement integrate tan^3(9x) Homework Equations tan^2(x)= sec^2(x)-1 integral of tanxdx= ln|secx| The Attempt at a Solution Integrate tan3(9x)dx Integral (sec2(x)-1)tan(9x)dx so then I distribute the tan(9x) giving me: integral tan(9x)sec2(x)dx - integral tan(9x) dx so then I solve...

Was it the micro?

Wow, that cleared up a lot so, r= 0.37J/((8.99e9)(5e-6)(3.3e-6)) ?

Homework Statement The potential energy of a system of two charges (q1 = 5.0 µC and q2 = 3.3 µC) is 0.37 J. What is the distance between the charges? Homework Equations U=(kq_0q)/r --> r=U/(kq_0q) U=V/q_0 V=0.37J q1 = 5.0 µC q2 = 3.3 µC The Attempt at a Solution So I was going to use...