Recent content by WelshDave

I've used the formula N(y)dy=M(X)dx first order separable ODE dvdt+(1/m)v=−g I'm guessing that should be dv/dt+(k/m)v= -g k=8.7 m= 80 v(0)=0 worked out a long formula and got, v(t)= -1/87e^-(87t/800)(7848e^(87t/800)-7848) Can you advise it that is correct. I looks right to me.

Good day all I am struggling with this one. m (d^2 h)/(dt^2 )+k dh/dt=-mg use v=dh/dt in place to turn 2nd order into 1st order so from this i have got (d^2 h)/(dt^2 )= -g-(v/m) Is this a first order equation? If so can somebody point me to solve the equation when m=80, k=8.7, v(0)=0ms-1...