Recent content by wheelhot

Hi, this is my first post here. I managed to solve the question. integrate sin(3x)^3 cos(3x)^5 dx = -cos(3x)^6/2 + 3cos(3x)^8/8 + c That is the answer that I get when I differentiate somewhere in the equation, u = cos 3x, du/-3 = sin(3x) dx. My question is, why do I get 2 different...