Recent content by whiteshado

yes i know about exponentials (notation correct?) umm i think i got to 45 or something this was yesterday logarithms i might know about them 3.13e13=1kw 3.13e15=100kw i can change all the zeros to 3.13e15 if you like and 3.2e-11 there you go

wow no one could help me with this question?

i formula perhaps? maybe a hint like what number it starts with? anything? no? sigh...

perhaps this question is harder than i think for the great minds that roam these fourms cannot direct me in the correct direction

During the fission of an atom of uranium-235, 200 Mev are released. If the average time between generations of fission reaction is 10e-14 seconds and if each fission reaction gives rise to two fissions in the next generation, calculate the time required to go from the first fission to 100 Kw...

for the question Calculate the energy (in Mev's) released in the reaction: 2/1H + 3/1H ->4/2He + 1/0n + E and i know 1 amu = 931 Mev

did i say that?

i have an answer in any season any weather smash the egg on the ground so taht the one end is now flat and it will stand up

i did do taht after i posted and tried useing the constant in ev form

one mroe question on this the energy lvl of 3 in a hydrogen atom is -1.5 and lvl 1 is -13.6 though my graph shows the infinity sign and a 0.0 for where lvl 6 should be could i get the energy lvl of lvl 6 from someone? or how to get it

ahh yes by useing Planck's constant in its original form thanks for the help again guys

=f=594574507617985878855444072835.38 correct?\ then speed of light/f=w 299 792 458/594574507617985878855444072835.38=5.04e-22 taht still doesn't give me the correct answer the correct answer is 1.22e-7

ahhh i devided instead of multiplying

hmm i got 1.15e53 10.2/1.6e-19/6.63e-34 its not right thought i think i missed soemthing wait is this is my freqwuancy correcT?

12.2? is that it? nope it was 10.2