Recent content by WilkinsD

Oops had 5.25 seconds should be 5.2 seconds

so I found this was for sure not provided by my teacher. That would be 0.1 = .52/t which would make t = 5.2 seconds correct?

So that just brings me back to the 0.522 radians per second lol

Torque=I*a

5 times per minute would be 12 seconds per turn. so it should be .083/sec.

So would that just be my torque which is 40 N * m and my I which is 400 kg*m^2 40=400a so that gives me my a=0.1 rad/s ?

Yeah but what formula solves for how long to apply the force to get the wheel to turn 5 times a minute ?

I must be slow today lol How long would you have to apply it to get the wheel spinning 5 times a minute? I can't wrap my head around the equation I need to solve to get how long I would have to apply the force to get it spinning 5 times a minute.

Alright so that gives me .52 rad/s

So 5 * 2pi? or 31.42 radians ?

The first time I solved it I got these as my answers but wasn't for sure if they were correct. 1. 300s 2. The acceleration would then be reduced to 0.0625 rad/s^2.

Maybe that is where I have messed up. Most of the problems my teacher provided were not setup in this manner.

No I believe that is my angular momentum before the 60kg person jumps on.

Homework Statement If the steel disk has mass of 200 kg and a radius of 2 meters you can make it spin by applying a force to the rim. This torque increases the angular momentum of the disk. Suppose the force is 20 Newtons. How long would you have to apply it to get the wheel spinning 5...