Recent content by wintermute++

Miswrote, meant amount function as specified in problem. And sorry, I was lazy and assumed too much of whoever was going to help me.

My bad. ## a(0) = 1 ## for accumulation functions.

The textbook writes True, True for the solutions, for whatever that's worth. My approach was: Since ## a'(t) = a'(0) ##, ## a(t) = a(0) = 1 ##. Then ## a'(t) = a(1) - 1 = 0 = a'(0) ##.

Homework Statement Suppose that an amount function ## a(t) ## is differentiable and satisfies the property ## a(s + t) = a(s) + a(t) − a(0) ## for all non-negative real numbers ## s ## and ## t ##. (a) Using the definition of derivative as a limit of a difference quotient, show that ## a'(t) =...

Thanks haruspex. You've been a great help for me so far.

Homework Statement How many different sets of birthdays are available with k people and 365 days when we don’t distinguish the same birthdays in different orders? Homework Equations [/B] I approached this using what was proven in a previous problem, provided I did that right. This what I had...

I see, very nice. Many thanks for your help earlier too.

Would you mind explaining how you got that answer? I get ## {n^k \over e^k} ##

If that were the case, it would be approximately 1, correct?

Step 1. ## n! = (2 \pi)^{1/2}n^{n+1/2}e^{-n} ## and ## (n-k)! = (2 \pi)^{1/2}(n-k)^{n-k+1/2}e^{-n+k} ## Step 2. ## {n! \over (n-k)!} = {(2 \pi)^{1/2}n^{n+1/2}e^{-n} \over (2 \pi)^{1/2}(n-k)^{n-k+1/2}e^{-n+k}} ##

Homework Statement Let n and k be positive integers such that both n and n − k are large. Use Stirling’s formula to write as simple an approximation as you can for Pn,k. Homework Equations ## \lim_{n \rightarrow \infty} {(2 \pi)^{1/2}n^{n+1/2}e^{-n} \over n!} = 1 ## The Attempt at a Solution...

Hey Maylis, are these the proper textbooks you're referring to? Transfer Phenomena --> For momentum, heat, and mass transfer by Bird et al. Elementary Principles of Chemical Processes -->Mass/Energy balance by Felder Thanks for your suggestions. Looks like I'll have a lot of interesting stuff...

Hey Smittron, thanks for the core outline! Do you recommend a specific sequence of courses to build upon each other? I'd like text recommendations for Thermodynamics (I have Atkins Physical Chemistry), Material and Energy Balances, and Process Design. But if one requires another to learn well...

Yes, I do see. I had tried your alternative method but didn't account for the vapor pressure of benzene, instead I used the boiling temperature of benzene which was 353.2 K. I really appreciate the help.

If I solve it as above, I get an enthalpy of formation of the metallocene equal to 141.0 kJ/mol. If I use the molar heat capacities to calculate the enthalpy of formation for gaseous benzene and ignore the liquid molar heat capacity and enthalpy of vaporization altogether, I get an enthalpy of...