Recent content by wirenut67

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Agreed and Thanks Again Al!

Again Al many thanks! In your opinion would this amount of force create a noticeable reaction from the vehicle occupants?

Al could I bother you for just a second to review this for me. I am posting this written like this so please look this over for me. We can calculate the force created by braking from 12mph to 8 mph in .5 seconds, and its force upon a 150lb human. To calculate the deceleration rate we take...

So the final result is that the force is 55.31 lbs of force?

So then 4.6875 slugs x 11.8 ft/s ^2 is a force of 55.31 slugs or 55.31 lbs of force?

mass = [150 lbs]/[32 ft/s²] =4.6875 slugs?

Understood so far. So my rate of deceleration is 11.8 ft/s² So now I move to force. Force= mass x deceleration. Is this correct Al? So my deceleration is 11.8ft/s² Where I am lost is in figuring the mass based on slugs. Can you show me how to do this?

So written correctly it should be: 17.6 ft/s²-11.7ft/s²= 5.9ft/s² and then 5.9 ft/s² /.5= 11.8 ft/s² Is this correct Sir?

So the final result would be 11.8 Ft/s²? Al I really appreciate your patience here. This is just something I am beginning to understand. Mike

Ok so for the first part I would use: Initial Velocity= 17.6 ft/s (12mph) Final Velocity = 11.7 ft/s (8mph) Deceleration time = .5 seconds So then 17.6-11.7= 5.9 ft/s 5.9ft/s /.5 seconds = 11.8 ft/s Is this correct for the first part of the calculation?

Are you telling me that mass will be 150 LBS divided by 32 slugs? This is the part I am not understanding.

Greetings, First post here. I am trying to calculate the force applied to a 150 lb. person riding in a vehicle that decelerates from 12mph to 8 mph in .5 seconds. If I am understanding correctly the formula is: Initial velocity-Final Velocity/.5 So 12-8/.5 = 8 The to calculate...