Recent content by wizard147

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    Graduate Taylor Series: Can't quite work it out

    Hi Tim, Thanks, I think when you factored out your i, and then multiplied top and bottom by i you would get -iR + iR/(1-z/iR) I could be wrong though! lol
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    Graduate Taylor Series: Can't quite work it out

    Hi Guys, Looking at some notes i have on conformal mapping and I have the following where z is complex and z* denotes its conjugate, R is a real number z* = -iR + R^2/(z-iR) and my lecturer says that using the taylor series we get, z* = -iR + iR(1+ z/iR + ...) I've been...
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    Graduate Having trouble working with modules

    Ah wait no, What I said that (g+h) isn't a basis element is wrong. It is an element of G and thus a basis element. Therefore we have (g+h).v = g.v +h.v implies v=v+v So I'm still stuck as to how we can get left action to be the identity. thought we almost had it! C
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    Graduate Having trouble working with modules

    Awesome, cheers Micromass! C
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    Graduate Having trouble working with modules

    Another question for you :), I've been playing around with these and had a look at a bit of representation theory. I was looking at group algebra's, where G is a finite group, and \mathbb{C} is our field. I was trying to find a C[G] module, V, that has a left action is the basis of C[G] (i.e...
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    Graduate Having trouble working with modules

    Ahhh, so simple! Thank you so much, I think i'll noodle around with them a bit more so I can understand them better. Really appreciate it. C
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    Graduate Having trouble working with modules

    Hi guys, Basically I'm playing around with modules at the moment, and I can't work out why we can't have the group of integers as an F-module (F a field), where the left action is the identity. i.e F x Z ----> Z where we have f.z = z f in F, z in Z If this were possible, then Z would be a...