Recent content by WTFsandwich

I think I got it now. After multiplying by x, I have ASx = SBx. Bx has already been shown equal to \lambdax, so I substitute that in, giving ASx = S\lambdax \lambda can be moved to the other side of S since it's a scalar, giving ASx = \lambdaSx.

What do I use to show that? The only new information I've got that might be helpful is that A = S * B * S^-1 Multiplying on the left by S gives A*S = S*B After doing that, I'm stuck again. I feel like this is the right track, but I don't know how to relate this back to what I'm trying...

Homework Statement Let B = S^-1 * A * S and x be an eigenvector of B belonging to an eigenvalue \lambda. Show S*x is an eigenvector of A belonging to \lambda. Homework Equations The Attempt at a Solution The only place I can think of to start, is that B*x = \lambda*x. However...

I know that's what I have to do, but I don't know how to go about doing it. I started the addition part up above, and am stuck at that point.

Homework Statement Suppose A is a vector \in R^{2x2}. Find whether the following set is a subspace of R^{2x2}. S_{1} = {B \in R^{2x2} | AB = BA} The Attempt at a Solution I know that S isn't empty, because the 2 x 2 Identity matrix is contained in S. The problem I'm having...

If I'm understanding you correctly, I should take the inverses of all the elementary matrices and multiply those, and it should give me A? Essentially, (E1E2...En)-1 = A

Homework Statement Given A = \left( \begin{array}{cc} 2 & 1 \\ 6 & 4 \end{array} \right) a) Express A as a product of elementary matrices. b) Express the inverse of A as a product of elementary matrices. Homework Equations The Attempt at a Solution Using the following EROs Row2 --> Row2 -...