Recent content by Yasin

Yes you are right and i did change the last one by editing the first post and i think i have solved it thanks for all support the solution is as follows in picture for any interested Some reason the textbook solution is wrong

The fall is any distance but here I assume when the part where 'm' is located is nearest to bottom that will be the max speed thus max angular velocity

Sorry, I am new and my attempt I tried converting mgh(gravitational potential energy) into (mv^2)/2 (Kinetic energy) b being the height i get mgb=mv^2/2 so i get 2gb=v^2 v^2/r^2 is w^2 so i get 2gb/b^2=w^2 which is sqr(2g/b) as the answer but somehow the answer in the book i use to study is...

Homework Statement Finding the general formula for max angular velocity ( answers say 0.839*(g/b)) but I do not understand how Homework Equations 0.839*(g/b) The Attempt at a Solution