Sorry, this has been asked a few times, but nothing's getting through to me. I really need to satisfy this curiosity :(
I've read a lot of "water wave" analogies, but they don't make sense.
A water wave has physical peaks and valleys, and I can see how when the peak travels and hits a ship, the...
So force on a current carrying wire = ILxB.
If I have a bunch of bar magnets making a uniform magnetic field of strength B, then a 1 meter long wire of 0 ohms carrying 1 Amp, the force on that wire is (1)(1)xB = 1B. If I let that force move the wire for a time T, let's assume the wire moved a...
So I'm confused what the Saturation Flux Density is referring to. Defintion says it is when you no longer get an increase in H-field when increasing external B-field.
So, does the satuation flux mean the core can only create fields UP TO that saturation flux, or that it can make a stronger...
So let's assume ideal wire, resistance = 0 Ohms. Also assume there is a magnetic ball 1 meter away and is attracted to the solenoid.
If you have a loop of wire and run a small current through it, you get a magnetic field. This field attracts the magnetic ball, over a distance of 1 meter.
If...
Ok, so dq represents the incremental charge to be applied on the capacitor plate and not an imaginary test charge between the plates?
I'm getting my original info from here, first paragraph:
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capeng2.html
Yes, that's where I am getting caught up. For a spring, each small distance you move affects the spring force, and that force is applied specifically for that small distance dx.
But for a capacitor, each small charge you add to the plate increases the voltage, but why is that voltage applied...
I know V = q/c and W = Vq and dW = V dq. But why is Work in charging a capacitor W = integral of q/c dq?
q seems to represent a charge on the capacitor plate and dq seems to represent a separate test charge. If I add a charge to the capacitor plate, I take take the resulting votage and multiply...
The reflection would be a wave bouncing off an incoming wave. S predicts you can add the two waves together to get the net wave, and that waves pass through each other.
For two different amplitudes, my R hypothesis says the colliding waves will reflect with their original amplitudes, while S...
Yes, this is exactly the mentality that I had when asking this question. Unfortunately, Orodruin's answer went a bit over my head. So here's my thought experiment.
We have a sound source producing a soundwave every second (1 Hz), the soundwave travels at 1 m/s, and there is a perfectly...