Recent content by zacl79

yep, exactly

Thanks Philip, i managed to get it sorted, i found an approximation for Lim Ptp->0 (P/Ptp), when i graphed P/Ptp Vs Pt so then was able to approximate the limit to find out my temperature. Thanks heaps

Homework Statement I have been given measurements of Ptp and corresponding values of P for mercury. My task is to calculate the idea-gas temperature Tg of the material to five significant figures. Ptp| 1000.0|750.00|500.00|250.00| P |1535.3 |1151.6| 767.82| 383.95| Homework...

Show the following matrix A is unitary and find its inverse. A = 1-2i, 2i -2i, -1-2i Ok, i have read over this sort of thing in my textbook, and it has an example, but i can't see where the numbers in the inverse come from. The textbook got two row vectors r1 and...

Thanks guys, Ill give it a go!

A 'cause' occurs at point 1 (x1, t1) and its 'effect' occurs at point 2 (x2, t2) as measured by observer O. Use Lorentz transformation to find t'2 - t'1 as measured by O' and show that t'2 - t'1 >= 0. that is Observer O' can never see the effect before the cause. I know that is possible to...

Thanks very much, i know understand how to do a problem like this should it creep up again, and i worked it all out for length to = 9 units. thanks heaps everyone

thanks ill get on to it and get back to you how it goes. thanks

so just to get this right, the x=25/a and y=16/b gets substituted into L = x^2 + y^2, isn't that just the same as i was doing before?? have you managed to get the answer to be 9 units??

okay, i rearranged and everything and got L=(-375b^2 + 6400)/(25b^2 - 25b^4/16) and then minimized to get something looking like this: (-320750/b -61250b - 3125b^3)/(25-25b^2/16) = 0 and I am not to sure how to solve it, that's if i minimized correctly!

Thanks for that, ill give it a go tomorrow and see if that works. Just outta interest have you solved the problem to get the minimum distance to be 9 units??

Sorry, the way i interpreted the question, is all i was saying. I didnt mean to say that my idea was right, i thought we were discussing the same idea, but i was wrong, I am sorry for any confusion.

okay as far as i got was setting up two equations for the coordinates at the x and y axes. y=-16a^2/25b -b x= 25b^2/16a + a Are you saying these now go into the L = x^2 + y^2 sqr((625b^4/256a^2 + 50ab^2/16 + a^2) + (256a^4/625b^2 -32ba^2/25 + b^2)) I know that is difficult to...

the way i interpretted it was that the point where the tangent touches of the minimal length will be the same poit as if i was to maximise the rectangle. Obviously not then. Im sorry if I am not picking up on something trivial, by taking a random point on the ellipse and construcing an...

oh i see, I am sorry that was a misunderstanding. I am aware that i can get x0 from y0 and vice versa. But its a matter of getting at least one point first, was i on the right track with the rectangle idea?