How Do You Calculate Ideal-Gas Temperature from Mercury Pressure Data?

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Homework Help Overview

The discussion revolves around calculating the ideal-gas temperature (Tg) using pressure data from mercury. The original poster presents measurements of total pressure (Ptp) and corresponding mercury pressure (P) values, along with a formula for Tg that involves the limit of the pressure ratio as P approaches zero.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss evaluating the ratios of P/Ptp for the given data and suggest looking for trends as P approaches zero. The original poster expresses uncertainty about their initial approach and seeks guidance.

Discussion Status

The discussion has progressed with the original poster indicating they found a way to approximate the limit needed for their calculations. Another participant confirms the temperature value derived from the discussion.

Contextual Notes

There is an emphasis on significant figures in the calculations, with a specific mention of using six significant figures for the ratios. The original poster's initial confusion about their approach highlights the complexity of the problem.

zacl79
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Homework Statement



I have been given measurements of Ptp and corresponding values of P for mercury. My task is to calculate the idea-gas temperature Tg of the material to five significant figures.

Ptp| 1000.0|750.00|500.00|250.00|
P |1535.3 |1151.6| 767.82| 383.95|

Homework Equations



Tg(K) = 273.16 lim Pt ->0 (P/Ptp)

The Attempt at a Solution



Ok i have read up on the ideal gas temperature scale, and sort of grasp it. I have graphed the table and got and equations relating the line to be:

P = 1.5351x +0.21

I don't believe that this is the right way to go about this problem. I am just asking for some direction, as i have hit a wall.

Thanks Zac
 
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I'm assuming that the 'material' is mercury.

I recommend you evaluate the ratios P/Ptp for each of the four pairs. Take 6 sig figs, i.e. 5 decimal places. You should notice a simple quantitative trend. So what looks to be the limit as P approaches zero?

Say if you get stuck.
 
Thanks Philip, i managed to get it sorted, i found an approximation for Lim Ptp->0 (P/Ptp), when i graphed P/Ptp Vs Pt so then was able to approximate the limit to find out my temperature.
Thanks heaps
 
419.56 k ?
 
yep, exactly
 

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