Recent content by Zander Forrester
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Have to find the stationary points on the graph y = 3sin^2x
Thanks for your reply. The textbook gave the three answers I submitted. With sin(2x) = 0 2x = 0, 180, 360, 540 and 720 X = 0,90,180, 270 and 360 X = 0, pi/2, pi, 3pi/2 and 2pi. Zander- Zander Forrester
- Post #11
- Forum: Calculus and Beyond Homework Help
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Have to find the stationary points on the graph y = 3sin^2x
Thank you again.- Zander Forrester
- Post #8
- Forum: Calculus and Beyond Homework Help
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Z
Have to find the stationary points on the graph y = 3sin^2x
Hello again Orodruin, Region was from 0 to 2pi. Thank you again for your help.- Zander Forrester
- Post #5
- Forum: Calculus and Beyond Homework Help
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Z
Have to find the stationary points on the graph y = 3sin^2x
Hello Orodruin, Thank you for your help. sin(x) = 0 x = Pi cos(x) = 0 x = pi/2 and 3pi/2- Zander Forrester
- Post #3
- Forum: Calculus and Beyond Homework Help
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Z
Have to find the stationary points on the graph y = 3sin^2x
Homework Statement Homework EquationsThe Attempt at a Solution [/B] y = 3sin^2x dy/dx = 3(2sinxcosx) dy/dx = 6sinxcosx For stationary points...- Zander Forrester
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- Graph Points
- Replies: 11
- Forum: Calculus and Beyond Homework Help