Recent content by Zarif

It is not clear from the question .. could be outside or inside

I don't know about "method of images" .. It would be very very helpful if you give me some idea

I know that potential is given by that equation . I don't have a problem in that

Homework Statement Find the potential of an uncharged metal sphere provided that a point charge q is located at a distance r from its center 2. The attempt at a solution As far as the charges are concerned , some negative charges will build up at the side of the charge because of induction ...

Thanks @PeroK .. Everything is quite clear now

Upgrade Your Physics by A. C. MACHACEK

Thanks, I do get the point now . But in the book it says ..let me quote "Notice in particular that the quantity (ΣE)2 = (Σpc)2 + (Σmoc2)2 when applied to a group of particles has two things to commend it.  Firstly, it is only a function of total energy and momentum, and therefore will remain...

I understand now , M comes to be (√((pc)2)+(m1c2)2 + √((pc)2)+(m2c2)2) / c2 so , that is not m1+ m2 .. i understand what i was doing wrong .. i was like writing (a+b)2= a2+b2. so what do the textbooks actually mean by "for a system of particle , (ΣE)2 = (Σpc)2 + (Σmoc2)2" ?

I don't have a good idea on how to approach.. Maybe you could give me some more hint

For a particle , E2 = (pc)2 + (moc2)2 and for a system of particle , (ΣE)2 = (Σpc)2 + (Σmoc2)2 so in that way before a collision, (ΣEi)2 = (Σpic)2 + (Σmoic2)2 and after , (ΣEf)2 = (Σpfc)2 + (Σmofc2)2 and as far as i know energy and momentum is conserved . so that means ΣEi=ΣEf and also Σpi=Σpf...