Recent content by Zayan

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Yes I meant to say that even though the fields are not uniform, we can equate the "flux" of that region as the decrease in flux and the increase of cos/theta sort of cancel each other out

Yes I understand that I even said it. My point is that even though the field on the plane area is not uniform, we can equate it with the flux passing through the cylindrical arc without doing the calculation? I suppose that even though the field is higher on the actual plane but the angle and...

The same number of lines that would have crossed the part of curved surface of the outer cylinder

Are you talking about the unitary method? Like dividing total flux in 2π and multiplying by 2*15° = 30°? I don't know I am kinda sceptical about that method. Is that valid? I mean the field is not constant for BC so can I still use that?

Okay makes sense. I did not know what edge effects they're referring to. So now my doubt is almost cleared I'll revise the earthing concept. So now for flux I'll calculate it through BC then multiply by two. So I take a strip of l length dx width and find the flux and integrate from π/4 to π/3.

Let me clear this up. What I'm asking is that how do you know that the entire outer charge will be neutralized by grounding, what's the proof for that? Earth makes the potential zero but that doesn't imply the whole charge will be neutralized does it? Also, note that the derivation for the...

I take a cylindrical surface as it is symmetric and calculate the field inside the region with the dielectric and it comes out as Q/2πrle⁰k

I get the point. Okay let me go through. Firstly the inner one is charged so all charge will be on the outer side of it as the field in the conductor is zero(by gauss's law). And due to that charge a negative charge is induced on the inner side of the outer one(-Q). But since it was neutral, it...

Okay I'll edit it. So for the first question I suppose after charging the inner cylinder, charge get's induced in the outer one too. And after grounding, charge is flown from the outer cylinder to make its potential zero. But I am not quite sure how much. Also, I am not quite sure how to write...

Y Are you referring to my reply or the main question? If it's the reply then yes I know but he asked the "total" flux. So it is q/e⁰.

I suppose it would be total charge of the inner cylinder over epsilon-naught.

This was asked in an exam. I'll share the photo of the question. Well firstly as the outer cylinder is grounded, it must have a zero potential. My first doubt is that is it like a capacitor? i.e, will there be any field outside the outer cylinder? If no then how so? I presumed that it won't...

Ohh that means the charges inside add up to the field to make it divergent and contribute to the flux?

So my question was that is the charge density inside the cube the cause of the field or the effect