Recent content by Zeke Bevan
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Newton's Third Law Problem: Two masses, a rope and a pulley
Okay, So fnet=3.675-mg?- Zeke Bevan
- Post #21
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
The forces acting on the other block are tension and weight as well. The acceleration is equal to the rate the other block is accelerating (3/4g). I think you can make the F=ma equation to be: Fnet=tension-weight. So, the tension be equal to 3.675N and weight is equal to mass times gravity with...- Zeke Bevan
- Post #19
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
Okay, what I am deciding on my net force to be is, tension minus weight. The tension which I am thinking is the acceleration (3/4g) times mass (1.5kg) minus the weight force (1.5kg times gravity.) This would give you 11.025-14.7= -3.675 N, was that the correct way of doing it or should it be...- Zeke Bevan
- Post #17
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
Yes I realized what I said that was my bad! Weight is a force in Newton’s, I meant to say multiple the rate at which it’s accelerating times the mass, I assume that’s a force but I’m guessing that’s not the correct way to get the tension, I’m really confused as of how.- Zeke Bevan
- Post #15
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
Okay. Would the tension be equal to the rate a which it’s accelerating times the weight?- Zeke Bevan
- Post #13
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
The tension in the rope that is going upwards and the weight of the block(1.5 times 9.8). So to find the net force, would it be Tension minus the weight?- Zeke Bevan
- Post #11
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
Okay I believe I understand what you are saying. So, for this problem, the tension would equal the mass(1.5kg) times the rate at which it's accelerating downward(3/4g)?- Zeke Bevan
- Post #9
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
I'm really sorry, I'm going through my textbook right now and I can't find anything on this, I can only find that in massless strings the tension will be equal for each object. I'm really bad at assumptions because I don't think I'll be right but I'm thinking it will be equal to the object...- Zeke Bevan
- Post #7
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
I can only think that the accelerations would be different? One object would be pull down while the other got pulled up. So for this problem would I use f=ma to find the tension of the rope getting pulled down?- Zeke Bevan
- Post #5
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
So, the forces acting on each block is gravity pulling the blocks down and tension in the rope holding the blocks together? If there is tension in the rope, can I assume there are equal to each other as well? I'm really sorry if am oblivious on how to do this problem, I'm finding myself to be...- Zeke Bevan
- Post #3
- Forum: Introductory Physics Homework Help
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Newton's Third Law Problem: Two masses, a rope and a pulley
Homework Statement Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of the blocks w/ a mass of 1.5 kg accelerates downward at (3/4)g. A. What is the mass of the other block? Homework Equations There were no given...- Zeke Bevan
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- Law Newton's third law Newtons laws of motion Newtons third law Pulley Rope Third law Two masses
- Replies: 21
- Forum: Introductory Physics Homework Help
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Can Undergraduate Physics Studies Boost Astronomy Career Prospects?
Hi everybody! My name is Zeke, I'm currently in my undergraduate studies and I'm hoping to major in astronomy! I''m currently taking physics, so I'm here to learn more about the subject and get any help along the road, which I'm sure I will. I look forward to meeting new people on here and wish...- Zeke Bevan
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- Replies: 2
- Forum: New Member Introductions