Recent content by zerojb34

so my final answer is now, I chose x=0 x^2 + (y-2.75)^2+(z-13/4)^2. right?

How can I do that? 3 variables with only two equations

i just did 3/5*(x0 +3/5)+4/5*(zo+4/5) this gives me a total of 4. So my new plane is 3x+4z=4. Is this right? If so I now have 3x+4z=4 and x-2y+2z=12. I know we must now use cross product, but not totally sure with what. Thanks in advance, Last step!

i follow you for plane one but not at all for plane two..confused with the multiplication. the new second plane is no longer parallel because it has different coefficients. would we be correct in saying, you find both planes, and then you need to find a new intersection of (x,y,z) which will be...

I'm honestly clueless at this point, could you please clarify a little bit. I understand the gist of what you are attempting to do but don't know how to arrive there. I have x=3+t y=-2t z=2t now what

I was thinking of doing that but I am unsure how (very new to 3 dimensional problems) Do you mean that each plane is parallel to both planes? i.e new plane 1 is parallel to both or just the first one.I don't know how you would find a parallel plane with knowing where it passes through...

When I take that cross product I get (-8,2,6). I don't know if that is the right way to go forward with the problem though.

Homework Statement Find the equation of a sphere of radius 3 which is tangent to both the planes x-2y+2z=3 and 3x+4z=8 Homework Equations The only eqn's I need are cross product and MAYBE the distance formula. The Attempt at a Solution Initially I shifted each normal vector by...