Recent content by zeromaxxx

  1. Z

    Cyclic Voltammetry

    it should be A but does that make a difference when the slope is calculated? since v1/2 is in mV/s and the slope would pretty much amount to the same value of 76.747?
  2. Z

    Cyclic Voltammetry

    Homework Statement Calculate the diffusion coefficient (cm2/s) of ferricyanide if cyclic voltammograms conducted on a solution of 1 mM KClO4 + 5 mM K4Fe(CN)6 at scan rates of 1, 2, 5, 10, 20, and 50 mV/s, resulted in peak currents of 76, 100, 175, 243, 348 and 552 mA. The electrode used for...
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    Compound Name

    I was reading my book on Inorganic Chem and I came across this compound that is part of a complex: B(C6F5)4. The book didn't say what the name of the compound was. Can anyone tell me the name?
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    Reaction Products

    Homework Statement For each reaction, give balanced chemical equations or NR (no reaction) and rationalize your answers in terms of trends in oxidation states. Calculate net potential for the reactions: a) Fe2+(aq) + Co3+ (aq) (acidic conditions) → b) CrO42−(aq) + MoO2(s) + H+ (acidic...
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    Analytical Chemistry

    Homework Statement CaCO3 acts as an antacid for temporary relief of heartburn/acid-reflux. Free calcium ions in solution can be analyzed gravimetrically after acid digestion and precipitation with oxalate in basic solution to form an insoluble calcium oxalate monohydrate salt that can be...
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    Complex Numbers Inequality

    Homework Statement Determine the region in the complex plane described by |z-2i| < |z+ i| Homework Equations z= x+ iy |z|= (x2 + y2)1/2 The Attempt at a Solution |z-2i| < |z+ i| |z-2i|/|z+ i| < 1 |z-2i| = [(x-2i)2 + y2]1/2 |z+ i| = [(x+i)2 + y2]1/2 [(x-2i)2 + y2]1/2...
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    Force Oscillations

    Homework Statement A lightly-damped oscillator is set in motion and observed as the oscillations decrease in amplitude. Derive approximate values for the factors by which i) the amplitude, and ii) the energy will decrease after Q cycles, where Q is the “quality parameter” defined in the...
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    Integral of x

    Homework Statement Integral of (k/x)-1/2 Homework Equations The Attempt at a Solution 2(k/x)1/2 How do I find the integral of the inner function (k/x)?
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    Angular Momentum and ball velocity

    Homework Statement A billiard ball (solid uniform sphere) is struck so that it has initial velocity v0, but no initial spin. As it slides along the table, friction causes it to spin, until eventually it is rolling without slipping. Find its speed when it begins to roll without slipping. Show...
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    Planetary Motion

    Homework Statement You are one of the first astronomers in a civilization on Planet B in another solar system. With your unaided eye, you follow planet A in the same solar system and note that it never gets further away than 16 degrees from the star (around which both planets orbit). What...
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    Quadratic Drag

    v at max height should be 0 right? so then 0 = -vt tanh (t/T) It's how to deal with the equation that comes after. tanh x = (ex - e-x)/(ex + e-x) tanh (t/T) = (et/T - e-t/T)/(et/T + e-t/T) 0 = -vt[ (et/T - e-t/T)/(et/T + e-t/T)] so if v = 0, then the the exponential functions...
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    Quadratic Drag

    Homework Statement A ball is thrown vertically upwards at speed v0. Assume drag force is proportional to v2. a) Show that, while moving upwards, Newton's Second Law gives a = -g(1+v2/vt2) where vt is the terminal speed. b) Take v0 = 3vt and solve for v(t), the time tmax at which it...
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    Isolate for Time

    Homework Statement I just need to isolate t from the equation though I'm stumped on how to do it. Homework Equations x(t) = vτ(1-e-t/τ) *τ and v are constants The Attempt at a Solution I know you somehow need to take the ln of both sides so ln x(t)/vτ = ln (1-e-t/τ) That's...
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    Classical Mechanics - Drag Force

    Hmm, it made more sense the way you put it though I still cannot determine the integral of t.
  15. Z

    Classical Mechanics - Drag Force

    Yes, sorry there's a typo in the original question I put up, the drag force is F = -cv3/2 and not 2/3. Sorry for this, I hope you can go through it again. Thanks!
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