Recent content by zhanglshi

oh right. so i got t=2.161 for the2nd stone to hit the ground. i used thex=x(not)=v(not)^2+(1/2)at^2 and got v(not)=-28.654. but according to my answers sheet its supposed to be -24.34. i have no idea what i did wrong..

but when the stone is at 0m, isn't its velocity 0?

i am confused on something. i didntt understand the problem well enough so i restarted my work. for the 1st stone, is the final velocity 0? if so, then when i used the v=v(initial)-at, my equation was 0=0+(-9.8)(t) and i got t=0. that is obviously false but idk what i did wrong.. i am terribly...

well the first stones velocity is 38.340m/s and the time is 3.912s. but idk where to go from there..

a stone is dropped from a 75m building. when this stone has dropped 15m, a second stone is thrown downaward with an initial velocity such that the two stones hit the ground at the same time. what was the initial velocity of the second stone? please use kinematic equations. that is all i know...