Recent content by zi-lao-lan
-
Z
Show how the Boltzmann entropy is derived from the Gibbs entropy for equilibrium
Thanks for the reply :) But I'm still not sure how you get to the last step. That means the the integral of dpdp = - omega, but I can't see why that is. Is it something to do with normalising it?- zi-lao-lan
- Post #3
- Forum: Advanced Physics Homework Help
-
Z
Show how the Boltzmann entropy is derived from the Gibbs entropy for equilibrium
Homework Statement Show how the Boltzmann entropy is derived from the Gibbs entropy for systems in equilibrium. Homework Equations Gibbs entropy S= - \int \rho(p,q) (ln \rho(p,q)) dpdq where \rho(p,q) is the probability distribution Boltzmann entropy S= ln\Omega where \Omega is...- zi-lao-lan
- Thread
- Boltzmann Entropy Equilibrium Gibbs
- Replies: 4
- Forum: Advanced Physics Homework Help
-
Z
Graduate Temperature distribution on a circular plate
Oh Thats really obvious, sorry :blushing:- zi-lao-lan
- Post #3
- Forum: Differential Equations
-
Z
Graduate Temperature distribution on a circular plate
Hi, I have a maths exam tomorrow (!) and I'm stuck on something: Its about solving LaPlace's equation in plane polar coordinates. There is a circular plate witha temp dist that satisfies (1/r)(d/dr(r.df/dr)) + 1/r2 . d2/dp2 = 0 (p is phi) so I used a separable eq of the form f=RP...- zi-lao-lan
- Thread
- Circular Distribution Plate Temperature
- Replies: 2
- Forum: Differential Equations